110 = 2 x 5 x 11.
110 is the product of a prime and the previous number: 110 = 11 x 10.
110 is the sum of three consecutive squares: 110 = 52 + 62 + 72.
1445 = 1335 + 1105 + 845 + 275: The first counterexample to disprove Euler’s conjecture that it always requires at least n terms (of nth power) to sum to an nth power, nontrivially.